HP 67 Collection: October 2026
All examples are done in FIX 4. (DSP 4)
Earth's Gravity at a Specific Latitude
The true earth gravity force depends on several factors, such as latitude and altitude. This estimation takes the latitude (north/south), in degrees-minutes-seconds, and latitude, in kilometers, into account.
The constant 9.80665 m/s^2 is an accepted average, the true force varies.
g_s = 9.806 – 0.026 * cos(2 * φ)
g_h = g_s * (6378.1 / (6378.1 + h))
HP 67 Code:
LBL A: 001 31, 25, 11
DEG: 002 35, 41
H←: 003 31, 74
2 : 004 02
× : 005 71
COS: 006 31, 63
. : 007 83
0 : 008 00
2 : 009 02
6 : 010 06
× : 011 71
9 : 012 09
. : 013 83
8 : 014 08
0 : 015 00
6 : 016 06
x<>y: 017 35, 52
- : 018 51
x<>y: 019 35, 52
6 : 020 06
3 : 021 03
7 : 022 07
8 : 023 08
. : 024 83
1 : 025 01
+ : 026 61
LST x: 027 35, 82
x<>y: 028 35, 52
÷ : 029 81
× : 030 71
RTN : 031 35, 22
Inputs:
Y: h
X: φ
Examples:
Inputs: h = 0, φ = 2°33’: g ≈ 9.7801
Inputs: h = 0.762, φ = 52°17’: g ≈ 9.8114
Source
Grainger Engineering Office of Marketing and Communications. (answer written by Rebecca H.) (2016, November 21). “How gravitational force varies at different locations on Earth.” Illinois. https://van.physics.illinois.edu/ask/listing/64061. Retrieved March 10, 2026.
Triangulation
With angles α and ß:
base = dist * (1/tan α + 1/tan ß)
dist = base ÷ (1/tan α + 1/tan ß)
Labels:
LBL A: Enter angles α and ß in the current angle mode. Returns 1/tan α + 1/tan ß.
LBL B: Base. When a number is entered prior to pressing [ B ], the number is stored as a base. Otherwise, the program solves for a base.
LBL C: Distance (of a line that bisects the base). When a number is entered prior to pressing [ C ], the number is stored as a base. Otherwise, the program solves for a base.
HP 67 Code:
LBL A: 001 31, 25, 11 (enter the angles)
TAN: 002 31, 64
1/x: 003 35, 62
x<>y: 004 35, 52
TAN: 005 31, 64
1/x: 006 35, 62
+: 007 61
STO 5: 008 33, 05
RTN: 009 35, 22
LBL B: 010 31, 25, 12 (base)
STO 3: 011 33, 03
F? 3: 012 35, 71, 03
RTN: 013 35, 22
RCL 4: 014 34, 04
RCL 5: 015 34, 05
× : 016 71
STO 3: 017 33, 03
RTN: 018 35, 22
LBL C: 019 31, 25, 13 (distance)
STO 4: 020 33, 04
F? 3: 021 35, 71, 03
RTN: 022 35, 22
RCL 3: 023 34, 03
RCL 5: 024 34, 05
÷ : 025 81
STO 4: 026 33, 04
RTN: 027 35, 22
Examples:
α = 30°, ß = 65°
Set degree mode. 30 [ ENTER ] 65 [ A ]. Result: 2.1984
Distance = 24, solve for base. 24 [ C ] [ B ]. Result: 52.7606
Base = 24, solve for distance. 24 [ B ] [ C ]. Result: 10.9172
Source:
“Triangulation (surveying)” Wikipedia. https://en.wikipedia.org/wiki/Triangulation_(surveying) (last edited October 24, 2025). Retried March 17, 2026
Time of Runoff on Turf
t = 2.5 * (L / (S * I^2))^(1/3)
t: time of runoff (rain off) in minutes
2.5: turf constant
L: distance from remote area in feet
S: slope of the terrain
I: rain intensity in inches per hour
Input Stack:
Z: L
Y: S
X: I
Output Stack:
X: t
HP 67 Code:
LBL A: 001 31, 25, 11
x² : 002 32, 54
× : 003 71
÷ : 004 81
3 : 005 03
1/x: 006 35, 62
y^x: 007 35, 63
2 : 008 02
. : 009 83
5 : 010 05
× : 011 71
RTN: 012 35, 22
Examples:
Inputs: Z: 900 ft, Y: 0.11, X: 4 in/hr. Result: 19.9917 min
Inputs: Z: 650 ft, Y: 0.33, X: 0.06 in/hr. Result: 204.4744 min
Source
Texas Instruments. Slide Rule Calculator SR-50A Manual. 1975. Manual from datamath.org: http://www.datamath.net/Manuals/SR-50A_US.pdf pg. 59
Beamwidth of a Radio Telescope
This program calculates the beam width of a radio telescope in degree-minutes-seconds.
Θ = 67625 ÷ (D * f)
Θ = beam width
D = the diameter of a circular telescope in feet
f = observing frequency in MHz (megahertz)
Inputs:
Y: D
X: f
Outputs:
X: Θ
HP 67 Code:
LBL B: 001 31, 25, 12
× : 002 71
1/x : 003 35, 62
6 : 004 06
7 : 005 07
6 : 006 06
2 : 007 02
5 : 008 05
× : 009 71
→H.MS: 10 32, 74
RTN: 11 35, 22
Examples:
Inputs: X: 1980 MHz, Y: 106 ft. Output: Θ: 0.1920 (19’20”)
Inputs: X: 1665 MHz, Y: 84 ft. Output: Θ: 0.2901 (29’01”)
Source
Ball, John A. Algorithms for RPN Calculators John Wiley & Sons: New York, NY. 1978. ISBN 0-471-03078-8. pg. 259
Fan Laws
p2 = (rpm2 ÷ rpm1)^n * p1
(p1 and p2 stand for various parameters, see the input syntax below)
Inputs:
1st law: (cfm: cubic feet per minute, rpm: revolutions per minute)
Calculate cfm2:
T: cfm1
Z: rpm2
Y: rpm1
X: 1
2nd Law: (sp: static pressure, rpm: revolutions per minute)
Calculate sp2:
T: sp1
Z: rpm2
Y: rpm1
X: 2
3rd Law: (hp: horsepower, rpm: revolutions per minute)
Calculate hp2:
T: hp1
Z: rpm2
Y: rpm1
X: 3
HP 67 Code:
LBL B: 001 31, 25, 12
R↓ : 002 35, 53
÷ : 003 81
R↑ : 004 35, 54
y^x: 005 35, 63
× : 006 71
RTN: 007 35, 22
Examples
1st Law: T: cfm1 = 2000, Z: rpm2 = 1100, Y: rpm1 = 950, X: n = 1
Result: cfm2 ≈ 2315.7895
2nd Law: T: sp1 = 0.5, Z: rpm2 = 1100, Y: rpm1 = 950, X: n = 2
Result: sp2 ≈ 0.6704
3rd Law: T: hp1 = 1.5, Z: rpm2 = 1100, Y: rpm1 = 950, X: n = 3
Result: hp2 ≈ 2.3286
Source
Gladstone, John. Air Conditioning Testing and Balancing: A Field Practice Manual A Van Nostrand Reinhhold Book. August 1976. pp. 24-32
More HP 67 goodness to come in November,
Eddie
All original content copyright, © 2011-2026. Edward Shore. Unauthorized use and/or unauthorized distribution for commercial purposes without express and written permission from the author is strictly prohibited. This blog entry may be distributed for noncommercial purposes, provided that full credit is given to the author.