Please take a look at the Fun With Num3ers blog by Benjamin Vitale (Twitter: @BenVitale). This is a fun blog working with number theory. It is also an inspiration for me to blog. Thanks, Ben!
Eddie
Link: http://benvitalenum3ers.wordpress.com/
On to today's blog entry!
Two Digit Numbers
Let AB represent a two digit number, where A and B each represent a digit 0 through 9 (excluding 00). My original goal was to find a number AB such that AB + BA = n where n contains both digits A and B. I was unsuccessful.
However, I did see something curious:
11 + 11 = 22
12 + 21 = 33
13 + 31 = 44
14 + 41 = 55
15 + 51 = 66
16 + 61 = 77
17 + 71 = 88
18 + 81 = 99
19 + 91 = 110
10 + 01 = 10 + 1 = 11
All the sums for this group are multiples of 11.
If I go on...
21 + 12 = 33
22 + 22 = 44
23 + 32 = 55
24 + 42 = 66
25 + 52 = 77
....
Once again, multiples of 11. Can we show that this is true for all sums AB + BA?
Let a represent the digit A. Similarly, let b represent the digit B. Then:
AB = (10a + b) and BA = (10b + a)
Then the sum AB + BA = (10a + b) + (10b + a) = 11a + 11b = 11(a + b)
Three Digit Numbers
Let's consider the number ABC. Rotate ABC one digit and add. Repeat. We get the sum ABC + BCA + CAB = n.
Let a, b, and c represent the digits A, B, and C, respectively. Then ABC = 100a + 10b + c. We can construct two similar sums for BCA and CAB.
Then
ABC + BCA + CAB
= (100a + 10b + c) + (100b + 10c + a) + (100c + 10a + b)
= 111a + 111b + 111c
= 111(a + b + c)
The sum is ends up a multiple of 111, but not necessarily of 11. (111 is not a multiple of 11). Examples?
Example 1:
425 + 254 + 542 = 1221
1221/111 = 11
1221/11 = 111
Example 2:
963 + 639 + 396 = 1998
1998/111 = 18
1998/11 = 181 6/11
1998 is not a multiple of 11
Can we find such triples ABC, BCA, and CAB such that the sum is divisible by both 11 and 111? Hint: the least common multiple of 11 and 111 is 1,221. I have found 31 such triplets (including the trivial 0,0,0).
If you want to find the triples, have fun! I'll leave you with a few examples:
29 + 902 + 290 = 1221. (029, 902, 290)
137 + 713 + 371 = 1221. (137, 713, 371)
598 + 859 + 985 = 2442. (598, 859, 985)
254 + 425 + 542 = 1221. (254, 425, 542)
Take care and be safe!
Eddie
This blog is property of Edward Shore. 2012
Sunday, December 16, 2012
Adding Numbers and their Reverses
New Background
The blog could use change in scenery: Eddie All original content copyright, © 2011-2026. Edward Shore. Unauthorized use and/or unautho...