HP Prime and TI-84 Plus
CE: Heat Properties of Water
Introduction
The program HEATH20
calculates three heat properties of liquid water based on its temperature. The program accepts three measurements for
liquid water, Fahrenheit (°F), Celsius (°C), or Kelvin (K).
Formulas Used:
Specific heat capacity
of water (amount of heat added or removed from an object to cause a temperature
change), measured in J/(g*°C):
C =
4.218 + 3.47*10^-4
*(T – 273)^2, for 233 K ≤ T < 274 K
4.175 + 1.3*10^-5 *
(T – 308)^2 + 1.6 * 10^-8 *(T-308)^4, for 274 K ≤ T ≤ 308 K
(slight adjustment
on the limits to allow for 273 K to be calculated using the former formula)
Latent heat of
evaporation, measured in kJ/kg:
V = 1000 * (2.5 *
(273.15/T)^(0.167 + 3.67 * 10^-4 *T))
Latent heat of
fusion, measured in kJ/kg:
M = 333.5 + 2.05 * T
– 0.0105 * T^2
HP Prime Program HEATH20
EXPORT
HEATH2O()
BEGIN
// Water Properties
// EWS 2018-01-28
// Seinfeld, Pandis
// Atmospheric Chemistry - 2006
// input of temperature
LOCAL ch,T,C,V,H;
INPUT({T,{ch,{"°F","°C","K"}}},
"Temperature",
{"Temp: ","Unit: "});
IF ch==1 THEN
T:=5/9*(T-32)+273.15; END;
IF ch==2 THEN
T:=T+273.15; END;
// Specific heat (liquid)
CASE
IF T≥233 AND T<274 THEN
C:=4.218+3.47ᴇ−4*(T-273)^2; END;
IF T≥274 AND T≤308 THEN
C:=4.175+1.3ᴇ−5*(T-308)+
1.6ᴇ−8*(T-308)^4; END;
DEFAULT
C:=0; END;
// Latent Heat: Evaporation
V:=(2.5*(273.15/T)^
(0.167+3.67ᴇ−4*T))*1000;
// Latent Heat: Fusion
M:=333.5+2.05*(T-273.15)
-0.0105*(T-273.15)^2;
// Results
PRINT();
PRINT("Temp: "+STRING(T)+"
K");
IF C≠0 THEN
PRINT("Spec. Heat-Liquid
(kJ/g*K)");
PRINT(STRING(C)+" kJ/(g*K)");
END;
PRINT("Latent Heat -
Evaporation:");
PRINT(STRING(V)+" kJ/kg");
PRINT("Latent Heat - Fusion");
PRINT(STRING(M)+" kJ/kg");
END;
TI-84 Plus CE Program HEATH20
"EWS
2018-01-28"
"SEINFELD,
PANDIS"
"ATMOSPHERIC
CHEMISTRY,2006"
Input
"TEMPERATURE: ",T
Menu("TEMP.
UNIT","°F",1,"°C",2,"K",3)
Lbl
1
5/9*(T-32)+273.15→T
Goto
3
Lbl
2
T+273.15→T
Goto
3
Lbl
3
0→C
If
T≥233 and T<274
Then
4.218+3.74E4*(T-273)^2→C
End
If
T≥274 and T≤308
Then
4.175+1.3E5*(T-308)^2+1.6E8*(T-308)^4→C
End
(2.5*(273.15/T)^(.167+3.67E4*T))*1000→V
333.5+2.05*(T-273.15)-.0105*(T-273.15)^2→M
ClrHome
Disp
"TEMP (K):",T
If
C≠0
Then
Disp
"SPEC. HEAT (KJ/(G*K)",C
End
Disp
"LATENT-EVAP. (KJ/KG)",V
Disp
"LATENT-FUSION (KJ/KG)",M
Example
0°C (273.15 K):
Results:
Temp: 273.15
K
Specific Heat: 4.218008415 kJ/(g*K)
Latent Heat –
Evaporation: 2500 kJ/kg
Latent Heat –
Fusion: 333.5 kJ/kg
Source:
John H. Seinfeld,
Spyros N. Pandis. Atmospheric
Chemistry and Physics: From Air Pollution to Climate Change, 2nd
Edition. John Wiley & Sons,
Inc: Hoboken, New Jersey. 2006 ISBN-13: 978-0-471-72018-8
Eddie
This blog is property
of Edward Shore, 2018.
