Construction Pro 5: Geometry Algorithms
Before We Begin
Before we begin, some things to note:
1. The [ Circ ] [ Circ ] sequence gives the area of a circle given by the denominator. Area = (π * diameter^2) / 4
2. The [ Conv ] [ Rcl ] will clear the Construction Master 5's memory register. So will [ Rcl ] [ Rcl ], the only difference is that the former sequence will not recall the memory's contents.
3. The [ Rcl ] [ M+ ] sequence will recall the memory register's contents.
4. The Construction Master 5 operates in Chain mode, like standard four-function calculators.
5. The algorithms presented today is one way to approach these calculation, most of them demonstrate the [ Circ ] [ Circ ] and memory features.
Area: Donut Driveway
Area = ((2D + I)^2 - I^2) * π/4
Key Sequence:
[ Conv ] [ Rcl ]
2 [ x ] D [ + ] I [ = ] [ Circ ] [ Circ ] [ M+ ]
I [ Circ ] [ Circ ] [ Conv ] ( M- )
[ Rcl ] [ M+ ]
Example:
D = 50 feet, I = 10 feet
[ Conv ] [ Rcl ]
2 [ x ] 50 [ Feet ] [ + ] 10 [ Feet ] [ = ] [ Circ ] [ Circ ] [ M+ ]
10 [ Feet ] [ Circ ] [ Circ ] [ Conv ] ( M- )
[ Rcl ] [ M+ ]
Result: 9,424.778 ft^2
Volume: One-Hole Concrete Block
Note: The border length (d) is equal around the entire block.
V = ( ( W + L ) * 2 * d - 4 * d^2 ) * t
Key Sequence:
[ Conv ] [ Rcl ]
W [ + ] L [ x ] 2 [ x ] d [ M+ ]
d [ Conv ] ( x^2 ) [ x ] 4 [ M- ]
[ Rcl ] [ M+ ] [ x ] t [ = ]
Example:
L = 12 in, W = 8 in, d = 1 in, t 10 in
[ Conv ] [ Rcl ]
8 [ Inch ] [ + ] 12 [ Inch ] [ x ] 2 [ x ] 1 [ Inch ] [ M+ ]
1 [ Inch ] [ Conv ] ( x^2 ) [ x ] 4 [ M- ]
[ Rcl ] [ M+ ] [ x ] 10 [ Inch ] [ = ]
Result: 360 in^3
Volume: Right Triangular Prism
V = D * H * B / 2
Key Sequence:
D [ x ] H [ x ] B [ ÷ ] 2 [ = ]
Example:
D = 325 ft, H = 77 ft, B = 148 ft
325 [ Feet ] [ x ] 77 [ Feet ] [ x ] 148 [ Feet ] [ ÷ ] 2 [ = ]
Result: 1,851,850 ft^3 ≈ 68,587.04 yd^3
Volume: Sphere Using the Circ Function
V = 4/3 * π * r^3 = π * d^3 / 6 = area_circle * d / 1.5
where area_circle = π * d^2 / 4
Key Sequence:
[ Conv ] [ Rcl ]
D [ M+ ] [ = ] [ Circ ] [ Circ ] [ x ] [ Rcl ] [ M+ ] [ ÷ ] 1.5 [ = ]
Note: The first equals key "locks" in the value of D on to the register and allows it to be picked up with the Circ function without having to re-type it.
Example:
D = 5 ft
[ Conv ] [ Rcl ]
5 [ Feet ] [ = ] [ M+ ] [ Circ ] [ Circ ] [ x ] [ Rcl ] [ M+ ] [ ÷ ] 1.5 [ = ]
Result: 65.44985 ft^3
Volume: Column Using the Circ Function
V = π * D^2 * H / 4 = area_circle * H
where area_circle = π * d^2 / 4
Key Sequence:
D [ Circ ] [ Circ ] [ x ] H [ = ]
Example:
D = 2 ft 2 in, H = 1 ft 8 in
2 [ Feet ] 2 [ Inch ] [ Circ ] [ Circ ] [ x ] 1 [ Feet ] 8 [ Inch ] [ = ]
Result: 6.145013 ft^3
Commas added for readability.
Eddie
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