Saturday, July 23, 2022

HP 32SII Applications: Moments of Inertia, Conductor Temperature Change, Slit Patterns

HP 32SII Applications: Moments of Inertia, Conductor Temperature Change, Slit Patterns


Moment of Inertia - Uniform Disk


The moment of inertia on a uniform disk of radius r is:


I = 2 * π * L * ρ * ∫(r^3 dr, 0, R) 


where ρ = M ÷ ( π * R^2 * L)


The formula of inertia for the uniform disk can be simplified to:


I = M * R^2 * 1/2

where

M = mass of the disk

R = radius of the disk

I = inertia of the center of the mass


HP 32SII Program:


I01  LBL I

I02  INPUT M

I03  INPUT R

I04  x^2

I05  ×

I06  2

I07  ÷

I08  RTN


(12.0 bytes, CK = B55F)


Example:

 

Inputs:

M = 8 kg

R = 0.2 m


Result:

I = 0.16 kg * m^2


Source:

Texas Instruments Incorporated.  Texas Instruments TI-55III Scientific Calculator Sourcebook  Second Edition.  1984



Conductor Temperature Change


The temperature change due to the change of the resistance can be calculated as:


∆t = 1 ÷ α * ( R_2 ÷ R_1 - 1)


where:

∆t = change of temperature in °C

R_2 = new resistance in Ω  (R)

R_1 = new resistance in Ω  (F)

α = temperature coefficient of resistance (A)  (see table below and source)


Selected Temperature Coefficients of Resistance at 20°C (α):


Material:  α


Nickel:  0.005866

Iron:  0.005671

Aluminum:  0.004308

Copper:  0.004041

Silver:  0.003819

Gold:  0.003715

Alloy Steel (99.% iron):  0.003


HP 32SII Program:


T01  LBL T

T02  INPUT A

T03  INPUT R

T04  INPUT F

T05  ÷

T06  1

T07  -

T08  x<>y

T09  1/x

T10  ×

T11 RTN


(16.5 bytes, CK = DDA9)


Example:


Inputs:

A = 0.004041  (α, Copper)

R = 58 Ω  (new resistance)

F = 50 Ω  (old resistance)


Result:

39.594160 °C


Sources:


"Temperature Coefficient of Resistance"  All About Circuits.  Last Retrieved May 17, 2022.  https://www.allaboutcircuits.com/textbook/direct-current/chpt-12/temperature-coefficient-resistance/#:~:text=The%20resistance%2Dchange%20factor%20per,with%20an%20increase%20in%20temperature.


National Radio Institute Alumni Association  Mathematics For Radiotricians Washington, D.C.  1942


Slit Patterns


The intensity of diffraction pattern of the single slit can be calculated by the formula:


I = Im * (sin α ÷ α)^2


where:

Im = potential maximum intensity

α = (π * s * sin θ ÷ λ) in radians

s = slit width

λ = wavelength in Hz

θ = angle of diffraction in degrees


For a double slit:


I = Im * (cos B)^2 * (sin α ÷ α)^2


where:

B is in radians and

B = (π * d * sin θ ÷ λ)

d = distance between slits

θ = angle of diffraction in degrees

α = see the single slit formula above


HP 32SII:

A:  θ

S:  slit wdith

W:  wavelength, λ

I:  maximum intensity


LBL S: single slit

LBL D: double slit, uses LBL S


HP 32SII Programs:


Single Slit:


S01  LBL S

S02  DEG

S03  INPUT A

S04  SIN

S05  INPUT S

S06  ×

S07  π

S08  ×

S09  INPUT W

S10  ÷

S11  RAD

S12  ENTER

S13  SIN

S14  x<>y

S15  ÷

S16  x^2

S17  INPUT I

S18  ×

S19  RTN


(28.5 bytes, CK = 40E0)


Double Slit:


D01  LBL D

D02  XEQ S

D03  DEG

D04  RCL A

D05  SIN

D06  INPUT D

D07  ×

D08  π

D09  ×

D10  RCL÷ W

D11  RAD

D12  COS

D13  x^2

D14  ×

D15  RTN


(22.5 bytes, CK = 8BC7)


Example:


Inputs:

A = 8°

S = 1.96E-6 m

W = 500E-9Hz

I  = 1


Single Slit Calculation:

XEQ S:  0.333496


Double Slit Calculation:

XEQ D

D = 3E-5 m

Result:  0.068409


Source:

Saul, Ken.  The Physics Collection:  Ten HP-41C Programs for First-Year Physics Class  Corvallis, OR.  1986



Coming up:  Python Week:  August 1 to August 5, 2022


Eddie


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