Sunday, September 17, 2023

Filling the Memory of a Casio fx-4000P

Filling the Memory of a Casio fx-4000P





How many programs does it take to fill the 550 step memory?   Here are six programs that pretty much does the job.   I purposely aimed for descriptive prompts and messages. 


Spaces are added for readability.  


Here's are the six programs:


Prg 1:  Approximating the cumulative distribution function of the Normal Curve - to 3 decimal places


Mode +:  COMP,  Number of Steps: 82


"Z≥0" : ?→Z : Fix 3 : 1 - ((1+.196854 Z +.115194 Z² + .000344 Z^3 + .019527 Z^4)^ -4) ÷ 2 : Rnd : Norm : "AREA=" ◢ Ans → A


Source:  Abramowitz and Stegun, Handbook of Mathematical Functions. 1972.


Examples:


Z = 1.6

Results:  AREA = 0.945


Z = 1

Results:  AREA = 0.841


For best results, enter a positive Z.  



Prg 2:  Binomial Distribution PDF with Mean and Variance 


Mode +: COMP, Number of Steps: 86


"P(WIN)" : ?→P : "TRIALS" : ?→T : "WINS" : ?→N : "PDF=" ◢ T nCr N × P x^y N × (1-p) x^y (T-N) ◢ "MU=" ◢ T P  ◢ "VAR=" ◢ Ans (1 - P)


Note:  The combination function, nCr, is shown on the screen as a lone solid C.  I have the nCr for clarification.  


P(WIN):  probability of a successful event

TRIALS:  number of events

WINS:  number of successful events

PDF:  probability of we get the number of successful events

MU:  expected value, mean - depending on P(WIN) and TRIALS

VAR:  variance - depending on P(WIN) and TRIALS


Example:


P(WIN) = 0.7,  TRIALS = 25, WINS = 10

Results:  PDF = 1.324897424 x 10^-3, MU= 17.5, VAR= 5.25   



Prg 3:  Angles of a triangle given 3 side lengths in Degrees - Solve a SSS (side-side-side) Triangle


Mode +: COMP,  Number of Steps: 86


Deg : "A" : ?→A : "B" : ?→B : "C" : ?→C : "<A=" ◢ cos^-1 ((A² + B² - C²) ÷ (-2 B C))  → D ◢ "<B=" ◢ sin^-1(B sin D ÷ A) → E ◢ "<C=" ◢ 180-D-E→F 


Angle <A  (stored in D) is opposite of side with length A

Angle <B (stored in E) is opposite of side with length B

Angle <C (stored in F) is opposite of side with length C


Degrees mode is set in the program.  


Example:

Triangle with lengths A = 24, B = 60, C = 44

Results:  <A = 20.04997572,  <B = 58.99241697, <C = 100.9576073



Prg 4:   Free Fall with Air Resistance (from Ke!san)  

Assume coefficient is standard at k = 0.24 kg/m

(angle is not needed, hyperbolic trig does not depend on angle unit)


Site:  https://keisan.casio.com/exec/system/1231475371

(last retrieved:  February 27, 2023)


Mode +:  COMP,  Number of Steps:  88


.24 → K : 9.80665 → G : "MASS" : ?→M : "DIST" : ?→D : √(M ÷ G ÷ K) → X : "TIME=" ◢ 

X cosh^-1 (e(D K ÷ M)) → T ◢ "VEL=" ◢ X G tanh(T ÷ X) → V


SI units are assumed.


Example:

MASS = 68 kg, DIST (free fall distance) = 1874 m

Results:  TIME = 39.27745305 s, VEL (velocity at free fall) = 52.71191359 m/s



Prg 5:  Sums of 1 to n for k, k^2, k^3, and K^4


Mode +:  COMP, Number of Steps:  83


"1 TO..." : ?→N : "K =" ◢ N (N+1) ÷ 2 → S ◢ "K²=" ◢ S (2 N + 1) ÷ 3 → T ◢ 

"K◢3=" ◢ S² → U ◢ "K◢4=" ◢ T (3 N² + 3 N - 1) ÷ 5 → V 



The power character, x^y can not be used in a string or an error occurs.  The stop character, ◢, can be used.  


K:   Σ (K from K = 1 to K = N)

K²:  Σ (K^2 from K = 1 to K = N)

K◢3:  Σ (K^3 from K = 1 to K = N)

K◢4:  Σ (K^4 from K = 1 to K = N)


Example:  

N = 9

Results:

K:  45

K²:  285

K◢3:  2025

K◢4:  15333



Prg 6:  Simple Ohm's Law Wheel/Volts, Current, Resistance:  "PIE" chart


Mode +:  COMP, Number of Steps: 121


Lbl 0 : "ENT 0 TO SLV" ◢ "I" ◢ ?→I : "V" ◢ ?→ V : "R" ◢ ?→R : I=0 ⇒ Goto 1 : V=0 ⇒ Goto 2:  R=0 ⇒ Goto 3: Goto 0:  Lbl 1:  "I="  ◢ V ÷ R → I ◢ Goto 4: Lbl 2: "V=" ◢ I R → V ◢ Goto 4: Lbl 3: "R=" ◢ V ÷ I → R ◢ Lbl 4: "END"


I:  current (amps, A)

V: voltage (volts, V)

R:  resistance (ohms, Ω)


The inputs will be in this order.  Enter a zero for the variable you want to solve for.  


Examples:


Solve for I:  I = 0, V = 12, R = 3

Result:  I = 4


Solve for V:  I = 20, V = 0, R = 30

Result:  V = 600


Solve for R:  I = 17, V = 120, R = 0

Result:  R ≈ 7.05






Total Number of Programs: 6

Total Steps Used: 121 (I only have 4 left)


Eddie



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