Casio fx-991CW: Recurrence Sequences
Introduction
Today’s edition we will work with recurring sequences, which can take the form of:
u_n = f(u_n-1), with initial condition u0
u_n = f(u_n-1, u_n-2) with initial conditions u0, u1
In general:
u_n = f(u_n-1, u_n-2, … u_n-k) with initial conditions u0, u1, u2, …, u_n-(k-1)
There is no app on the Casio fx-991CW that is dedicated to be recurrence sequences.
Recurring Sequences the Quick and Easy Way with the Calculate App
A quick way to tackle recurrence sequences and involves the use of the last answers key ( [Ans] ). This works on recurrence sequences with only one initial condition, u0.
Start by entering u0 and press [ EXE ]. Then enter the recurrence function, using Ans as u_(n-1).
Example:
u_n = 0.75 * u_(n-1)^2 + 1.03 * u_(n-1) with u0 = 1
Settings: MathI/DecimalO (Input/Output), Number Format (Norm 1)
1 [ EXE ]
0.75×Ans²+1.03×Ans [ EXE ] (Disp: 1.78)
[ EXE ] (Disp: 4.2097)
[ EXE ] (Disp: 17.62717157)
[ EXE ] (Disp: 251.1938698)
[ EXE ] (Disp: 47582.49986)
…
Recurrence Sequences with the Spreadsheet App
A way to generate recurrence sequences is to use the Spreadsheet app. The app contains a spreadsheet of size 5 columns (A, B, C, D, E) by 45 rows. Depending on the number of the initial conditions, up to 44 terms can be generated.
For the purposes of this blog, we’ll use column A, but we can use any column, as long as there is memory in the Spreadsheet.
u_n = f(u_n-1), with initial condition u0
Set A1 as the value of u0.
At cell A2:
1. Press [ TOOLS ].
2. Select Fill Formula and press [ OK ].
3. Enter the recurrence function, using A1 as u_(n-1).
4. At the range, set as A2:A#, to create a list of #-1 terms. For example, the range A2:A11 to create a list of 10 terms.
5. Select Confirm and press [ OK ].
Example:
Under Show Cell, Value (using the [TOOLS] menu)
u_n = (u_(n-1) + 0.5) * u_(n-1) with u0 = 0.65 for 7 terms.
Cell A1 = 0.65
Cell A2:
Fill Formula:
Form = (A1+0.5)×A1
Range: A2:A8
|
A (display) |
1 |
0.65 |
2 |
0.7475 |
3 |
0.93250625 |
4 |
1.335821031 |
5 |
2.452328343 |
6 |
7.240078475 |
7 |
56.03877556 |
8 |
3168.363754 |
u_n = f(u_n-1, u_n-2), with initial condition u0, u1
Set A1 as the value of u0.
Set A2 as the value of u1.
At cell A3:
1. Press [ TOOLS ].
2. Select Fill Formula and press [ OK ].
3. Enter the recurrence function, using A1 as u_(n-2) and A2 as u_(n-1).
4. At the range, set as A3:A#, to create a list of #-2 terms. For example, the range A2:A11 to create a list of 9 terms.
5. Select Confirm and press [ OK ].
Example:
u_n = u_(n-1) + u_(n-2), u0 =1 , u1 = 1 for 7 terms.
Yes, this is ripe for the Fibonacci sequence.
Cell A1 = 1
Cell A2 = 1
Cell A3:
Fill Formula:
Form = A1+A2
Range: A3:A9
|
A (display) |
1 |
1 |
2 |
1 |
3 |
2 |
4 |
3 |
5 |
5 |
6 |
8 |
7 |
13 |
8 |
21 |
9 |
34 |
Until next time,
Eddie
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