Please take a look at the Fun With Num3ers blog by Benjamin Vitale (Twitter: @BenVitale). This is a fun blog working with number theory. It is also an inspiration for me to blog. Thanks, Ben!
Eddie
Link: http://benvitalenum3ers.wordpress.com/
On to today's blog entry!
Two Digit Numbers
Let AB represent a two digit number, where A and B each represent a digit 0 through 9 (excluding 00). My original goal was to find a number AB such that AB + BA = n where n contains both digits A and B. I was unsuccessful.
However, I did see something curious:
11 + 11 = 22
12 + 21 = 33
13 + 31 = 44
14 + 41 = 55
15 + 51 = 66
16 + 61 = 77
17 + 71 = 88
18 + 81 = 99
19 + 91 = 110
10 + 01 = 10 + 1 = 11
All the sums for this group are multiples of 11.
If I go on...
21 + 12 = 33
22 + 22 = 44
23 + 32 = 55
24 + 42 = 66
25 + 52 = 77
....
Once again, multiples of 11. Can we show that this is true for all sums AB + BA?
Let a represent the digit A. Similarly, let b represent the digit B. Then:
AB = (10a + b) and BA = (10b + a)
Then the sum AB + BA = (10a + b) + (10b + a) = 11a + 11b = 11(a + b)
Three Digit Numbers
Let's consider the number ABC. Rotate ABC one digit and add. Repeat. We get the sum ABC + BCA + CAB = n.
Let a, b, and c represent the digits A, B, and C, respectively. Then ABC = 100a + 10b + c. We can construct two similar sums for BCA and CAB.
Then
ABC + BCA + CAB
= (100a + 10b + c) + (100b + 10c + a) + (100c + 10a + b)
= 111a + 111b + 111c
= 111(a + b + c)
The sum is ends up a multiple of 111, but not necessarily of 11. (111 is not a multiple of 11). Examples?
Example 1:
425 + 254 + 542 = 1221
1221/111 = 11
1221/11 = 111
Example 2:
963 + 639 + 396 = 1998
1998/111 = 18
1998/11 = 181 6/11
1998 is not a multiple of 11
Can we find such triples ABC, BCA, and CAB such that the sum is divisible by both 11 and 111? Hint: the least common multiple of 11 and 111 is 1,221. I have found 31 such triplets (including the trivial 0,0,0).
If you want to find the triples, have fun! I'll leave you with a few examples:
29 + 902 + 290 = 1221. (029, 902, 290)
137 + 713 + 371 = 1221. (137, 713, 371)
598 + 859 + 985 = 2442. (598, 859, 985)
254 + 425 + 542 = 1221. (254, 425, 542)
Take care and be safe!
Eddie
This blog is property of Edward Shore. 2012
A blog is that is all about mathematics and calculators, two of my passions in life.
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