Application
|
C
|
C
for HALFSTEP
|
Free-Fall
|
d^2y/dt^2 = g
|
“9.80665”
(SI) or “32.1740468” (US)
|
Free-Fall with
Friction
|
d^2y/dt^2 = g
- α (dy/dt)^2
(α = F/m)
|
“g - α * A^2”
(sub numeric
values for g, α)
|
Spring
|
d^2x/dt = -k/m
* x
|
“-k/m * T”
(sub numeric
values for k, m)
|
Pendulum
|
d^2θ/dt = -α*sin(θ)
(α = -g/l)
|
“-α * sin(Y)”
(sub numeric
values for α)
|
Damped,
Driven Oscillations
|
d^2x/dt = -α*x
– β*dx/dt + γ * sin(ω*t)
|
“-α*Y-β*A+γ*sin(ω*T)”
(sub numeric
values for α, β, γ)
|
Sunday, November 27, 2016
TI-84 Plus and HP Prime: Differential Equations and Half-Increment Solution, Numerical Methods
Friday, May 16, 2014
fx-5800p Programs (can apply to Casio graphing calculators also, e.g. fx-9860g, Prizm)
This is a collection of programs I wrote on the Casio fx-5800p. These programs should also work on any Casio Graphing calculator (fx-9860g, fx-9750g, Prizm) since the programming language between Casio calculators remains largely the same.
Now if I can find my fx-5800p that I misplaced last night... *sigh*. Thank goodness for notes!
Notes for the fx-5800p programs:
There are no SIGN or MOD functions. Here are the work arounds I used (see SUN):
SIGN(x):
...
X > 0 ⇒ 1 → X
-X > 0 ⇒ -1 → X
...
n MOD d:
...
N - D Intg( N ÷ D ) → result variable
....
Table of Contents:
1. Rotation of (x, y) (ROTATEXY)
2. Law of Cosines (COSINES)
3. Pendulum: Period and Average Velocity (PENDULUM)
4. Arc Length of a Parabola (QUADLENGTH)
5. Position of the Sun (SUN)
1. fx-5800p: ROTATEXY
Rotates the coordinate (X, Y). The direction of rotation follows the conventional direction (counterclockwise). The variable A represents the angle (θ).
Program:
"X"? → X
"Y"? → Y
"ANGLE"? → A
[ [ X, Y ] ] × [ [ cos(A), sin(A) ] , [ -sin(A), cos(A) ] ]
2. fx-5800p: COSINES
Sides: D, E, F
Corresponding Angles: A, B, C
Program:
Lbl 0
Cls
"KNOWN:"
"1. D,E,F"
"2. A,E,F"
?→I
I = 1 ⇒ Goto 1
I = 2 ⇒ Goto 2
Goto 0
Lbl 1
"D"? → D : "E"? → E : "F"? → F
"A" : cos ⁻¹ (( E ² + F ² - D ² ) ÷ ( 2EF )) → A ◢
"B": cos ⁻¹ (( D ² + F ² - E ² ) ÷ ( 2DF )) → B ◢
"C" : 180° - A - B
Stop
Lbl 2
"A"? → A : "E"? → E : "F"? → F :
"D": √ (E ² + F ² - 2 E F cos A ) → D ◢
"B" : cos ⁻¹ ( ( D ² + F ² - E ² ) ÷ (2DF)) → B ◢
"C": 180° - A - B
3. fx-5800p: PENDULUM
Variables:
D = length of the step or bar holding the pendulum
L = length of the rod or string that is swinging
R = large radius of the circular ring
At the units, enter 0 for US units (set g = 32.174 ft/s^2), anything else for SI units (g = 9.80665 m/s^2).
Calculated:
T = period of the pendulum (the amount of time it takes for the pendulum from one end to the other)
V = average velocity of the pendulum (once in its in full swing)
Program:
Cls
"=0 U.S."
"≠0 SI"
? → G
If G = 0
Then 32.174 → G
Else g → G IfEnd // g from the constant menu (9.80665)
Lbl 0
Cls
"1. ROD 2. STRING"
"3. RING"
?→ I
I = 1 ⇒ Goto 1
I = 2 ⇒ Goto 2
I = 3 ⇒ Goto 3
Goto 0
Lbl 1
"D"? → D : "L"? → L
2 π √( L ÷ 3G ) → T : Goto 4
Lbl 2
"D"? → D : "L"? → L
2 π √(L ÷ G) → T : Goto 4
Lbl 3
"D"? → D : "L"? → L : "R"? → R
2 π √( R ² ÷ GL → T : Goto 4
Lbl 4
"T =" : T ◢ "V =": D ÷ T → V
-----
Test Examples:
Rod: D = 1 m, L = 1.6 m. Results: T = 14.36943096 sec, V = .0695921782 m/s
String: D = 2 m, L = 1.75 m. Results: T = 2.65423008 sec, V = .07535141995 m/s
Circular Ring: D = 2 ft, L = 2 ft, r = 1.2 ft
Results: T = 1.879851674 sec, V = 1.063913727 m/s
4. fx-5800p: QUADLENGTH
Find the length of a parabola given height and width and a corresponding equation:
f(x) = Ax^2 + Bx
Where
A = -4h/l^2
B = 4h/l
Program:
Cls
"LENGTH"? → L
"HEIGHT"? → H
Cls
"COEF OF X ²"
-4 H ÷ L ² ◢
"COEF OF X"
4 H ÷ L ◢
"ARC LENGTH"
∫ ( √ ( 1 + ( -8 H X ÷ L ² + 4 H ÷ L ) ) , 0, L)
Test Data:
L: 16.4, H: 8.2
X^2 coefficient: -.1219512195
X coefficient: 2
5. fx-5800P: SUN
Source for the formulas: http://aa.usno.navy.mil/faq/docs/SunApprox.php
Gives the RA (right ascension) and δ (declination) of the sun at any date. U is the universal time, the time it would be at Greenwich Village (Int'l Date Line).
For the Pacific Time Zone:
Standard Time: PST + 8 hours = UT
Daylight Savings Time: PDT + 7 hours = UT
Program:
"MONTH"? → M
"DAY?" → D
"YEAR"? → Y
"UNIV. TIME"? → U
Deg
100 Y + M - 190002.5 → X
X > 0 ⇒ 1 → X
-X > 0 ⇒ -1 → X
367 Y - Intg( 7 ( Y + Intg( ( M + 9 ) ÷ 12 ) ) ÷ 4 )
+ Intg( 275 M ÷ 9 ) + D + 1721013.5 + U ÷ 24
- .5 X + .5 → D
D - 2451545 → D
357.529 + .98560028 D → G
G - 360 Intg( G ÷ 360 ) → G
280.459 + .98564736 D → Q
Q - 360 Intg( Q ÷ 360 ) → Q
Q + 1.915 sin( G ) + .02 sin( 2G ) → L
L - 360 Intg( L ÷ 360 ) → L
1.00014 - .01671 cos( G ) - .00014 cos( 2 G ) → R
23.439 - .00000036 D → E
tan ⁻¹ (cos(E) tan(L)) → A
If L ≥ 90 And L < 270
Then A + 180 → A
IfEnd
If L ≥ 270 And L < 360
Then A + 360 → A
IfEnd
A ÷ 15 → A
sin ⁻¹ ( sin(E) sin(L) ) → C
"APPROX:"
"RA (HRS)": A ◢
"DEC (DEG)": C
Test Data:
M: 5
D: 14
Y: 2014
U: 19
RA: 3.43 hours
DEC: 18.746°
Eddie
This blog is property of Edward Shore. 2014
Sunday, May 11, 2014
Casio fx-3650p: Programming
HAPPY MOTHER'S DAY! Love you Mom! Thanks for all you do - Eddie
Casio fx- 3650p Programs
To celebrate the recent procurement of a Casio fx-5800p, let's dedicate the next several posts to Casio programming calculators. This one is for the fx-3650p, a programming calculator sold world wide (not so much the United States :( ).
Some pointers about the fx-3650p:
* The fx-3650P has only 7 variables (A, B, C, D, X, Y, and M). To save space, variables are recycled.
* You can apply storage arithmetic to memory M, mainly M+ and M-. On the fx-3650P, M+ and M- can be programmable steps. I am not sure if this is possible on programming models (fx-50f, fx-4500p, etc), but this option is not present in Casio's fx-5800p and current graphing calculators (fx-9860, Prizm, etc).
* With Goto and Label, loops can be constructed. The fx-3650p has four comparative tests (=, ≠, >, and ≥).
* Take advantage of not having to close the final parenthesis and begin able to use implicit multiplication to save space.
With that, here are some programs.
Contents:
1. Circular Sectors
2. Stopping Sight Distance
3. Resistors in Parallel
4. Net Present Value
5. Rod Pendulum
6. Vectors: Dot and Cross Products
Circular Sector
Input:
A = radius
B = angle in degrees
Formulas:
arc length = 2 * r * sin(θ*π/360)
chord length = (r * θ * π)/180
Program: (28 steps)
? → A : ? → B : Deg :
2 A sin ( B π ÷ 360 ◢ A B π ÷ 180
Example:
A = 3.6
B = 44°
Input: Prog # 3.6 EXE 44 EXE
#: 1, 2, 3, or 4, depending on where your program is stored.
Results (to four decimal points);
0.04825 (chord length) EXE
2.7646 (arc length)
Stoping Sight Distance (U.S. Units)
Input:
A = design vehicle speed in miles/hour
B = grade, as a percentage
Standard constants (acceleration of the car of 11.2 ft/s^2 and 2.5 seconds of reaction time) are used.
Source: Goswami, Indramil Ph.D. P.E. "All In One Civil Engineering PE Breadth and Depth Exam Guide" 2nd Edition. McGraw Hill: 2012
Formula:
SSD = 11/3 * v + (1.075*v^2)/(11.2 + .32G)
Program: (32 steps)
? → A : ? → B :
11 A ⌟ 3 + 1.075 A ² ⌟ ( 11.2 + .32 B
Example 1: 50 mph, grade of 0%
Input: Prog # 50 EXE 0 EXE
Result: 423.4 mph
Example 2: 65 mph, grade of -2%
Input: Prog # 65 EXE -2 EXE
Result: 668.8 mph
The next two programs make use of loops.
Total Resistance: Resistors in Parallel
Formula: (1/R1 + 1/R2 + 1/R3 + ... )⁻¹
Note: The fx-3650P allows us to take the M+ to our advantage. Enter each resistor in Ohms. When completed, enter 0 to exit the loop.
Program: (30 steps)
0 → M :
Lbl 0 : ? → A : A = 0 ⇒ Goto 1 :
A ⁻¹ M+ : Goto 0 :
Lbl 1 : M ⁻¹
Example: A circuit has three resistors in parallel of 4 Ω, 3. Ω, and 6 Ω.
Input: Prog # 4 EXE 3 EXE 6 EXE 0 EXE
Result: 1.33333333
Net Present Value
Formulas: Σ (A_M / (1 + B%)^M) for M = 0 to C
Variables:
A = cash flows
B = periodic interest rate
C = number of cash flow (entered in advance)
Calculated Variables:
M = counter
D = total
Program: (51 steps)
? → C : ? → B : 0 → M : 0 → D :
Lbl 0 : ? → A :
D + A ÷ ( 1 + .01 B ) ^ M → D : 1 M+ :
C ≥ M ⇒ Goto 0 : D
Example:
Cash Flow:
CF0 = -$1,000.00
CF1 = $0.00
CF2 = $500.00
CF3 = $750.00
CF4 = $1,000.00
Periodic Interest Rate = 10%
Number of Flows = 4 (don't count the initial flow)
Input:
Prog #
4 EXE (number of flows)
10 EXE (periodic Interest rate)
-1000 EXE (cash flows)
0 EXE
500 EXE
750 EXE
1000 EXE
Results: $659.72 (NPV)
Pendulum of the Rod (U.S. units)
(See the above diagram).
A = length of rod
D = length of the board holding the rod
Formulas:
T = 2 π √( I / (m*g*A))
I = inertia of the pendulum
m = mass of the object
g = gravity constant (9.80665 m/s^2, 32.174 ft/s^2)
Using the rod, where I = 1/3 * m * r^2,
T = 2 * π * √(A/96.522) (US units) or
T = 2 * π * √(A/29.41995) (SI units)
Average velocity: V = D/T
Source: Michael Browne, Ph.D. "Schaum's Outlines: Physics for Engineering and Science" 2nd Edition. McGraw Hill, 2010
Program: (24 bytes for US Units)
? → A : ? → D :
2 π √ ( A ÷ 96.522 ◢ D ÷ Ans
Example:
A = 6 ft., D = 1.4 ft
Input: Prog # 6 EXE 1.4 EXE
Results:
1.566543062 sec (T) EXE
0.89368753 ft/sec (V)
Vectors: Dot and Cross Products
Formulas:
Dot Product:
[A, B, C] • [D, X, Y] = A*D + B*X + C*Y
[A, B, C] × [D, X, Y] = [ B*Y-C*X, C*D-A*Y, A*X-B*D ]
Program: (50 bytes)
? → A : ? → B : ? → C :
? → D : ? → X : ? → Y :
A D + B X + C Y ◢
B Y - C X ◢
C D - A Y ◢
A X - B D
Example:
[ 3, 4, 6 ] • [ -1, 2, 3 ] = 23
[ 3, 4, 6 ] × [ -1, 2, 3 ] = [ 0, -15, 10 ]
Input:
Prog # EXE 3 EXE 4 EXE 6 EXE -1 EXE 2 EXE 3 EXE
Results:
23 (dot product) EXE
0 (cross product, x) EXE
-15 (cross product, y) EXE
10 (cross product, z)
Hope that you enjoy these programs, maybe got a few pointers. Have a great day. I will be working with the Casio fx-5800p for my next blog, which I target to put out next week.
Peace!
Eddie
This blog is property of Edward Shore. 2014
Trigonometry Reduction Formula and Solving Simple Arcsine and Arccosine Equations
Trigonometry Reduction Formula and Solving Simple Arcsine and Arccosine Equations Some Background and Periodic Reduction Formulas ...

