HP 67 Collection: October 2026
All examples are done in
FIX 4. (DSP 4)
Earth's Gravity at a
Specific Latitude
The true earth gravity
force depends on several factors, such as latitude and altitude.
This estimation takes the latitude (north/south), in
degrees-minutes-seconds, and latitude, in kilometers, into account.
The constant 9.80665
m/s^2 is an accepted average, the true force varies.
g_s = 9.806 – 0.026 *
cos(2 * φ)
g_h = g_s * (6378.1 /
(6378.1 + h))
HP 67 Code:
LBL
A: 001 31, 25, 11
DEG:
002 35, 41
H←:
003 31, 74
2
: 004 02
×
: 005 71
COS:
006 31, 63
.
: 007 83
0
: 008 00
2
: 009 02
6
: 010 06
×
: 011 71
9
: 012 09
.
: 013 83
8
: 014 08
0
: 015 00
6
: 016 06
x<>y:
017 35, 52
-
: 018 51
x<>y:
019 35, 52
6
: 020 06
3
: 021 03
7
: 022 07
8
: 023 08
.
: 024 83
1
: 025 01
+
: 026 61
LST
x: 027 35, 82
x<>y:
028 35, 52
÷
: 029 81
×
: 030 71
RTN
: 031 35, 22
Inputs:
Y: h
X: φ
Examples:
Inputs: h = 0, φ =
2°33’: g ≈ 9.7801
Inputs: h = 0.762, φ =
52°17’: g ≈ 9.8114
Source
Grainger Engineering
Office of Marketing and Communications. (answer written by Rebecca
H.) (2016, November 21). “How gravitational force varies at
different locations on Earth.” Illinois.
https://van.physics.illinois.edu/ask/listing/64061.
Retrieved March 10, 2026.
Triangulation
With angles α and ß:
base = dist * (1/tan α
+ 1/tan ß)
dist = base ÷ (1/tan α
+ 1/tan ß)
Labels:
LBL A: Enter angles α
and ß in the current angle mode. Returns 1/tan α + 1/tan ß.
LBL
B: Base. When a number is entered prior to pressing [ B ], the
number is stored as a base. Otherwise, the program solves for a
base.
LBL
C: Distance (of a line that bisects the base). When a number is
entered prior to pressing [ C ], the number is stored as a base.
Otherwise, the program solves for a base.
HP
67 Code:
LBL
A: 001 31, 25, 11 (enter the angles)
TAN:
002 31, 64
1/x:
003 35, 62
x<>y:
004 35, 52
TAN:
005 31, 64
1/x:
006 35, 62
+:
007 61
STO
5: 008 33, 05
RTN:
009 35, 22
LBL
B: 010 31, 25, 12 (base)
STO
3: 011 33, 03
F?
3: 012 35, 71, 03
RTN:
013 35, 22
RCL
4: 014 34, 04
RCL
5: 015 34, 05
×
: 016 71
STO
3: 017 33, 03
RTN:
018 35, 22
LBL
C: 019 31, 25, 13 (distance)
STO
4: 020 33, 04
F?
3: 021 35, 71, 03
RTN:
022 35, 22
RCL
3: 023 34, 03
RCL
5: 024 34, 05
÷
: 025 81
STO
4: 026 33, 04
RTN:
027 35, 22
Examples:
α =
30°, ß = 65°
Set
degree mode. 30 [ ENTER ] 65 [ A ]. Result: 2.1984
Distance
= 24, solve for base. 24 [ C ] [ B ]. Result: 52.7606
Base
= 24, solve for distance. 24 [ B ] [ C ]. Result: 10.9172
Source:
“Triangulation
(surveying)” Wikipedia.
https://en.wikipedia.org/wiki/Triangulation_(surveying)
(last edited October 24, 2025). Retried March 17, 2026
Time
of Runoff on Turf
t =
2.5 * (L / (S * I^2))^(1/3)
t:
time of runoff (rain off) in minutes
2.5:
turf constant
L:
distance from remote area in feet
S:
slope of the terrain
I:
rain intensity in inches per hour
Input
Stack:
Z:
L
Y:
S
X:
I
Output
Stack:
X:
t
HP
67 Code:
LBL
A: 001 31, 25, 11
x²
: 002 32, 54
×
: 003 71
÷
: 004 81
3
: 005 03
1/x:
006 35, 62
y^x:
007 35, 63
2
: 008 02
.
: 009 83
5
: 010 05
×
: 011 71
RTN:
012 35, 22
Examples:
Inputs:
Z: 900 ft, Y: 0.11, X: 4 in/hr. Result: 19.9917 min
Inputs:
Z: 650 ft, Y: 0.33, X: 0.06 in/hr. Result: 204.4744 min
Source
Texas
Instruments. Slide Rule Calculator SR-50A Manual. 1975.
Manual from datamath.org:
http://www.datamath.net/Manuals/SR-50A_US.pdf
pg. 59
Beamwidth
of a Radio Telescope
This
program calculates the beam width of a radio telescope in
degree-minutes-seconds.
Θ =
67625 ÷ (D * f)
Θ =
beam width
D =
the diameter of a circular telescope in feet
f =
observing frequency in MHz (megahertz)
Inputs:
Y:
D
X:
f
Outputs:
X:
Θ
HP
67 Code:
LBL
B: 001 31, 25, 12
×
: 002 71
1/x
: 003 35, 62
6
: 004 06
7
: 005 07
6
: 006 06
2
: 007 02
5
: 008 05
×
: 009 71
→H.MS:
10 32, 74
RTN:
11 35, 22
Examples:
Inputs:
X: 1980 MHz, Y: 106 ft. Output: Θ: 0.1920 (19’20”)
Inputs:
X: 1665 MHz, Y: 84 ft. Output: Θ: 0.2901 (29’01”)
Source
Ball,
John A. Algorithms for RPN Calculators
John Wiley & Sons: New York, NY. 1978. ISBN 0-471-03078-8.
pg. 259
Fan
Laws
p2 =
(rpm2 ÷ rpm1)^n * p1
(p1
and p2 stand for various parameters, see the input syntax below)
Inputs:
1st
law: (cfm: cubic feet per minute, rpm: revolutions per minute)
Calculate
cfm2:
T:
cfm1
Z:
rpm2
Y:
rpm1
X:
1
2nd
Law: (sp: static pressure, rpm: revolutions per minute)
Calculate
sp2:
T:
sp1
Z:
rpm2
Y:
rpm1
X:
2
3rd
Law: (hp: horsepower, rpm: revolutions per minute)
Calculate
hp2:
T:
hp1
Z:
rpm2
Y:
rpm1
X: 3
HP
67 Code:
LBL
B: 001 31, 25, 12
R↓
: 002 35, 53
÷
: 003 81
R↑
: 004 35, 54
y^x:
005 35, 63
×
: 006 71
RTN:
007 35, 22
Examples
1st
Law: T: cfm1 = 2000, Z: rpm2 = 1100, Y: rpm1 = 950, X: n = 1
Result:
cfm2 ≈ 2315.7895
2nd
Law: T: sp1 = 0.5, Z: rpm2 = 1100, Y: rpm1 = 950, X: n = 2
Result:
sp2 ≈ 0.6704
3rd
Law: T: hp1 = 1.5, Z: rpm2 = 1100, Y: rpm1 = 950, X: n = 3
Result:
hp2 ≈ 2.3286
Source
Gladstone,
John. Air Conditioning Testing and Balancing: A Field Practice
Manual A Van Nostrand
Reinhhold Book. August 1976. pp. 24-32
More HP 67 goodness to come in November,
Eddie
All
original content copyright, © 2011-2026. Edward Shore.
Unauthorized use and/or unauthorized distribution for commercial
purposes without express and written permission from the author is
strictly prohibited. This blog entry may be distributed for
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author.