Subroutines
This session will show how routines work in HPPL. Generally, subroutines have be declared before the main program. Declaration is important. The details of the subroutines are after the main program.
Definitely take a look at the example programs to get a better understanding.
SUB Routines for HP Prime
General Syntax:
sub(); //declare subroutines
EXPORT main()
BEGIN
commands go here, including sub()
END;
sub()
BEGIN
commands go here
END;
This session will show how routines work in HPPL. Generally, subroutines have be declared before the main program. Declaration is important. The details of the subroutines are after the main program.
Definitely take a look at the example programs to get a better understanding.
SUB Routines for HP Prime
General Syntax:
sub(); //declare subroutines
EXPORT main()
BEGIN
commands go here, including sub()
END;
sub()
BEGIN
commands go here
END;
SUBEXAM
This is just a demonstration of how sub routines work. This program calculates one of two values:
If A is positive, then the program evaluates A. If not, the program values B instead. Where:
A = 2(x-y)/Φ + xy
B = Φ^2
and Φ = 2e^(x+y) - e^(x-y) - e^(y-x)
We will use Φ as the subroutine.
SUB1();
EXPORT SUBEXAM(X,Y)
BEGIN
LOCAL A, B;
A:=(2*(Y-X))/SUB1(X,Y)+X*Y;
B:=(SUB1(X,Y))^2;
IF A>B THEN
RETURN A;
ELSE
RETURN B;
END;
END;
SUB1(X,Y)
BEGIN
RETURN 2*e^(X+Y)-e^(X-Y)-e^(Y-X);
END;
Examples:
SUBEXAM(-4, 1) returns 21998.918189
SUBEXAM(2,3) returns 86283.2797974
SUBEXAM(-5,-6) returns 30.648061288
SUBEXAM(2,-3) returns 21810.6046664
Days Between Dates
DDAYS Using Subroutines for HP Prime: Best for 1901 to 2099
* Remember century years not divisible by 400 are NOT leap years. This program does not take this into account. If any such years are passed, subtract one day for such year manually.
Source: HP 12C Manual - Hewlett Packard
// Declare Subroutines
SUB1();
SUB2();
SUB3();
// Main program
EXPORT DDAYS(m1,d1,y1,m2,d2,y2)
BEGIN
// ΔDYS HP 12C
LOCAL x1, x2, z1, z2;
x1:=SUB1(m1); x2:=SUB1(m2);
z1:=SUB2(m1,y1); z2:=SUB2(m2,y2);
RETURN SUB3(y2,m2,d2,z2,x2)-
SUB3(y1,m1,d1,z1,x1);
END;
SUB1(X)
BEGIN
IF X≤2 THEN
RETURN 0;
ELSE
RETURN IP(.4*X+2.3);
END;
END;
SUB2(X,Y)
BEGIN
IF X≤2 THEN
RETURN Y-1;
ELSE
RETURN Y;
END;
END;
SUB3(Y,M,D,Z,X)
BEGIN
RETURN 365*Y+31*(M-1)+D+IP(Z/4)-X;
END;
(Thanks to Owitte for pointing out my typo)
Examples:
Days Between Dates:
7/3/1985 to 2/28/1995 is 3,527 days
3/14/1977 to 11/17/2013 is 13,397 days
12/10/2010 to 6/30/2014 is 1,298 days
1/5/2015 to 3/19/2227 returns 77,506 BUT this program treats 2100 and 2200 as leap years, which in reality they are not. Subtract 2 to get the correct answer of 77,504 days.
So that is how subroutines work. Please give comments, ask questions, and always thanks to my supporters and readers. Cheers!
Eddie
This blog is property of Edward Shore. 2013
