HP 15C: Reactance
Chart Solver
Source: HP-65 E.E. PAC 1. Hewlett Packard. September 1974. pg. 8-9
Equation:
2 * π * f *
√(L*C) = 1
Variables:
R0 = f =
Resonant Frequency (Hz)
R1 = L =
inductance (henrys)
R2 = C =
capacitance (farads)
Instructions:
Enter the
known values in each of the variables.
Enter the number of the variable to be solved in register I ( [ STO ] [
TAN ] (I) ). To solve, enter a range,
and press [ f ] [ ÷ ] (SOLVE), [ y^x ] (D). (*or whatever label you assigned
this program to)
Program:
|
Step
|
Key
|
Key Code
|
|
001
|
LBL D
|
42, 21, 14
|
|
002
|
STO (i)
|
44, 24
|
|
003
|
2
|
2
|
|
004
|
π
|
43, 26
|
|
005
|
*
|
20
|
|
006
|
RCL* 0
|
45, 20, 0
|
|
007
|
RCL 1
|
45, 1
|
|
008
|
RCL* 2
|
45, 20, 2
|
|
009
|
√
|
11
|
|
010
|
*
|
20
|
|
011
|
1
|
1
|
|
012
|
-
|
30
|
|
013
|
RTN
|
43, 32
|
Example:
L = R1 = 2.5
H, f = R0 = 60 Hz. Calculate C
(R2). Store 2 in RI.
Result: R ≈ 2.8145 E-06 (use range 0 to 1)
This blog is property of Edward Shore. 2016
