This is a collection of programs I wrote on the Casio fx5800p. These programs should also work on any Casio Graphing calculator (fx9860g, fx9750g, Prizm) since the programming language between Casio calculators remains largely the same.
Now if I can find my fx5800p that I misplaced last night... *sigh*. Thank goodness for notes!
Notes for the fx5800p programs:
There are no SIGN or MOD functions. Here are the work arounds I used (see SUN):
SIGN(x):
...
X > 0 ⇒ 1 → X
X > 0 ⇒ 1 → X
...
n MOD d:
...
N  D Intg( N ÷ D ) → result variable
....
Table of Contents:
1. Rotation of (x, y) (ROTATEXY)
2. Law of Cosines (COSINES)
3. Pendulum: Period and Average Velocity (PENDULUM)
4. Arc Length of a Parabola (QUADLENGTH)
5. Position of the Sun (SUN)
1. fx5800p: ROTATEXY
Rotates the coordinate (X, Y). The direction of rotation follows the conventional direction (counterclockwise). The variable A represents the angle (θ).
Program:
"X"? → X
"Y"? → Y
"ANGLE"? → A
[ [ X, Y ] ] × [ [ cos(A), sin(A) ] , [ sin(A), cos(A) ] ]
2. fx5800p: COSINES
Sides: D, E, F
Corresponding Angles: A, B, C
Program:
Lbl 0
Cls
"KNOWN:"
"1. D,E,F"
"2. A,E,F"
?→I
I = 1 ⇒ Goto 1
I = 2 ⇒ Goto 2
Goto 0
Lbl 1
"D"? → D : "E"? → E : "F"? → F
"A" : cos ⁻¹ (( E ² + F ²  D ² ) ÷ ( 2EF )) → A ◢
"B": cos ⁻¹ (( D ² + F ²  E ² ) ÷ ( 2DF )) → B ◢
"C" : 180°  A  B
Stop
Lbl 2
"A"? → A : "E"? → E : "F"? → F :
"D": √ (E ² + F ²  2 E F cos A ) → D ◢
"B" : cos ⁻¹ ( ( D ² + F ²  E ² ) ÷ (2DF)) → B ◢
"C": 180°  A  B
3. fx5800p: PENDULUM
Variables:
D = length of the step or bar holding the pendulum
L = length of the rod or string that is swinging
R = large radius of the circular ring
At the units, enter 0 for US units (set g = 32.174 ft/s^2), anything else for SI units (g = 9.80665 m/s^2).
Calculated:
T = period of the pendulum (the amount of time it takes for the pendulum from one end to the other)
V = average velocity of the pendulum (once in its in full swing)
Program:
Cls
"=0 U.S."
"≠0 SI"
? → G
If G = 0
Then 32.174 → G
Else g → G IfEnd // g from the constant menu (9.80665)
Lbl 0
Cls
"1. ROD 2. STRING"
"3. RING"
?→ I
I = 1 ⇒ Goto 1
I = 2 ⇒ Goto 2
I = 3 ⇒ Goto 3
Goto 0
Lbl 1
"D"? → D : "L"? → L
2 π √( L ÷ 3G ) → T : Goto 4
Lbl 2
"D"? → D : "L"? → L
2 π √(L ÷ G) → T : Goto 4
Lbl 3
"D"? → D : "L"? → L : "R"? → R
2 π √( R ² ÷ GL → T : Goto 4
Lbl 4
"T =" : T ◢ "V =": D ÷ T → V

Test Examples:
Rod: D = 1 m, L = 1.6 m. Results: T = 14.36943096 sec, V = .0695921782 m/s
String: D = 2 m, L = 1.75 m. Results: T = 2.65423008 sec, V = .07535141995 m/s
Circular Ring: D = 2 ft, L = 2 ft, r = 1.2 ft
Results: T = 1.879851674 sec, V = 1.063913727 m/s
4. fx5800p: QUADLENGTH
Find the length of a parabola given height and width and a corresponding equation:
f(x) = Ax^2 + Bx
Where
A = 4h/l^2
B = 4h/l
Program:
Cls
"LENGTH"? → L
"HEIGHT"? → H
Cls
"COEF OF X ²"
4 H ÷ L ² ◢
"COEF OF X"
4 H ÷ L ◢
"ARC LENGTH"
∫ ( √ ( 1 + ( 8 H X ÷ L ² + 4 H ÷ L ) ) , 0, L)
Test Data:
L: 16.4, H: 8.2
X^2 coefficient: .1219512195
X coefficient: 2
5. fx5800P: SUN
Source for the formulas: http://aa.usno.navy.mil/faq/docs/SunApprox.php
Gives the RA (right ascension) and δ (declination) of the sun at any date. U is the universal time, the time it would be at Greenwich Village (Int'l Date Line).
For the Pacific Time Zone:
Standard Time: PST + 8 hours = UT
Daylight Savings Time: PDT + 7 hours = UT
Program:
"MONTH"? → M
"DAY?" → D
"YEAR"? → Y
"UNIV. TIME"? → U
Deg
100 Y + M  190002.5 → X
X > 0 ⇒ 1 → X
X > 0 ⇒ 1 → X
367 Y  Intg( 7 ( Y + Intg( ( M + 9 ) ÷ 12 ) ) ÷ 4 )
+ Intg( 275 M ÷ 9 ) + D + 1721013.5 + U ÷ 24
 .5 X + .5 → D
D  2451545 → D
357.529 + .98560028 D → G
G  360 Intg( G ÷ 360 ) → G
280.459 + .98564736 D → Q
Q  360 Intg( Q ÷ 360 ) → Q
Q + 1.915 sin( G ) + .02 sin( 2G ) → L
L  360 Intg( L ÷ 360 ) → L
1.00014  .01671 cos( G )  .00014 cos( 2 G ) → R
23.439  .00000036 D → E
tan ⁻¹ (cos(E) tan(L)) → A
If L ≥ 90 And L < 270
Then A + 180 → A
IfEnd
If L ≥ 270 And L < 360
Then A + 360 → A
IfEnd
A ÷ 15 → A
sin ⁻¹ ( sin(E) sin(L) ) → C
"APPROX:"
"RA (HRS)": A ◢
"DEC (DEG)": C
Test Data:
M: 5
D: 14
Y: 2014
U: 19
RA: 3.43 hours
DEC: 18.746°
Eddie
This blog is property of Edward Shore. 2014
A blog is that is all about mathematics and calculators, two of my passions in life.
Friday, May 16, 2014
fx5800p Programs (can apply to Casio graphing calculators also, e.g. fx9860g, Prizm)
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Hi Eddie, so I had a question for you, I'm a cnc machinist and I use some basic geometry and trig. I had a calculator by "calculated industries" it was handy. Quite clever really. All you did was enter a numerical value and press "oop, adj, hyp, angles" and it would solve for trig functions as well as Pythagorean Therom. Do you think it would be possible to write a program to do this on this calulator?
ReplyDeleteThe formula with the Matris is a little bit wrong:
ReplyDelete[[X,Y]]×[[cos(A),sin(A)],[sin(A),cos(A)]]
the right one is:
[[X,Y]]×[[cos(A),sin(A)][sin(A),cos(A)]]
(without the second komma)
i think the comma means the next row on the matrix
ReplyDeletecan you make a mohr circle that takes stresses as inputs and asks for a specific rotation?
ReplyDeletePlease Can you write 3° 4° and 5° derivative program. casio fx 5800 has got 1° and 2° derivative.
ReplyDeleteAnybody have piping formula to programming for Casio fx5800p give all details or send my on email sonuguptabrp@gmail.com
ReplyDeletePls
Anybody have piping formula to programming for Casio fx5800p give all details or send my on email sonuguptabrp@gmail.com
ReplyDeletePls
I have started creating programs using FX5800P calculator for civil engineers and recently uploaded horizontal and vertical curve, which is may be first video and not available yet in the youtube. And further going to upload programs usefull for surveyor and compare with Autocad dimensions for verification.
ReplyDeleteChannel link click below.
https://www.youtube.com/channel/UC1bymDinXRoPCA2lVTOsgkQ?view_as=subscriber